NIMCET 2021
In three throws of three dice, the probability of throwing triplets not more than twice is
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Answer: Option D โ
Detailed Solution
A triplet (all three dice show the same number) in one throw: 6 favourable cases out of , so .
'Not more than twice' in 3 throws fails only if all three throws give triplets, with probability .
Required probability .
โ Check
Adding the binomial cases 0, 1, 2: .โ Common trap
(B) treats a triplet as one particular triple such as (6, 6, 6) in a single throw.Quick tip
P(triplet) ; not more than twice
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Ask a doubtMore Binomial Distribution Questions
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Binomial Distribution โ Preparation
This question tests your understanding of Binomial Distribution, a key topic in the Quantitative Aptitude section. The detailed solution above uses a step-by-step approach to show the reasoning, and where available, a shortcut that helps you solve similar questions in under 90 seconds during the actual exam.
The binomial distribution models the number of successes in a fixed number of independent trials, where each trial has only two outcomes (success or failure) and the probability of success p stays the same. Examples include the number of heads in ten coin tosses or the number of defective items in a sample. The probability of exactly r successes in n trials is P(X = r) = nCr p^r q^(n-r), where q = 1 - p. The mean is np and the variance is npq. Exam questions test finding the probability of exactly, at least or at most r successes, and finding n, p or q when the mean and variance are given. For "at least one" questions, use the complement: P(X >= 1) = 1 - q^n. Since the mean np is always greater than the variance npq, an option that gives a variance larger than the mean can be ruled out straight away. Practise the binomial distribution questions below, each with a step-by-step solution.