Computer Number System Questions with Solutions

Floating point numbers in a computer are represented using a $10$ -bit mantissa (including a sign bit) and a $7$ -bit exponent (including a sign bit). What is the approximate value of the maximum number which can be represented? Assume that the mantissa is stored in the normalised form, that is, without leading zeroes.

The addition of 4-bit, 2's complement binary numbers $1101$ and $0100$ results in

Given $\sqrt{{\left(224\right)}_r}={\left(13\right)}_r$, the value of the radix $r$ is

Let $A=11111010$ and $B=00001010$ be two 8-bit 2's complement numbers. Their product in 2's complement is

The decimal equivalent of ${\left(101101\right)}_2$ is:

The hexadecimal equivalent of ${\left(156\right)}_{10}$ is:

The binary equivalent of ${\left(725\right)}_8$ is:

Which of the following is NOT a valid octal number?

The decimal equivalent of ${\left(100101\right)}_2$ is:

The decimal equivalent of ${\left(11111111\right)}_2$ is:

The decimal equivalent of ${\left(634\right)}_8$ is:

The decimal equivalent of ${\left(3E8\right)}_{16}$ is:

The decimal equivalent of ${\left(0.11\right)}_2$ is:

The decimal equivalent of ${\left(A.C\right)}_{16}$ is:

The binary equivalent of ${\left(99\right)}_{10}$ is:

The binary equivalent of ${\left(256\right)}_{10}$ is:

The octal equivalent of ${\left(345\right)}_{10}$ is:

The hexadecimal equivalent of ${\left(750\right)}_{10}$ is:

The octal equivalent of ${\left(0.375\right)}_{10}$ is:

The binary equivalent of ${\left(6.125\right)}_{10}$ is: