NIMCET 2023 ยท NIMCET 2015
The locus of the mid-points of all chords of the parabola which are drawn through its vertex is
Answer (Detailed Solution Below)View answer โพHide โด
Answer: Option B โ
Detailed Solution
A chord from the vertex ends at a point of .
Its midpoint is , so : the locus is .
โ Check
: the chord ends at , the midpoint is , and .โ Common trap
(A) doubles the coordinates instead of halving them.Quick tip
Midpoint of and is
๐ฌ Discussions on this question
Ask a doubt โบStill stuck on this question? Ask our faculty and fellow students โ answers appear here.
Ask a doubtMore Parabola Questions
View all โบ- Q1.Which of the following equations can represent a common tangent to the parabolas and ?
- Q2.The equation of a parabola is . Which of the following points lies on the parabola?
- Q3.The directrix of the parabola is
- Q4.The equation of a parabola is . Which of the following points lies on the parabola?
- Q5.A point P in the first quadrant lies on , , and is at a distance from its focus. Which of the following points lies on the locus of P?
More Quantitative Aptitude Questions
- Q1.By selling 45 lemons for โน40, a man loses 20%. How many lemons should he sell for โน24 to gain 20%?Profit, Loss & Discount
- Q2.The marked price of an article is 1.45 times its cost price. Its selling price is โน1,500 and the profit is 25%. What is the discount percentage? Profit, Loss & Discount
- Q3.Let A be a real number. Then the roots of the equation are real and distinct if and only if Quadratic Equations
- Q4.The number of distinct real roots of the equation is Quadratic Equations
- Q5.The roots of are:Quadratic Equations
Parabola โ Preparation
This question tests your understanding of Parabola, a key topic in the Quantitative Aptitude section. The detailed solution above uses a step-by-step approach to show the reasoning, and where available, a shortcut that helps you solve similar questions in under 90 seconds during the actual exam.
A parabola is the set of points equidistant from a fixed point (the focus) and a fixed line (the directrix), so its eccentricity is exactly 1. The standard form y^2 = 4ax has its vertex at the origin, focus at (a, 0), directrix x = -a, and latus rectum of length 4a. The other standard forms open left, up or down. Exam questions test identifying the focus, directrix, axis and latus rectum, the parametric point (at^2, 2at), focal distances, and equations of tangents and normals. A key result is that the line y = mx + c touches y^2 = 4ax when c = a/m. Drawing a quick sketch of which way the parabola opens prevents most sign errors. Practise the parabola questions below, each with a step-by-step solution.