Question 21 of 63 · Permutations & Combinations
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NIMCET 2010

There are 6 tasks and 6 persons. Task 1 cannot be assigned to person 1 or person 2. Task 2 must be assigned to either person 3 or person 4. Every person is to be given exactly one task. In how many ways can the assignment be done?

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Answer: Option A — 144

Detailed Solution

1

Task 2 goes to person 3 or 4: ways.

2

Task 1 cannot go to person 1 or 2, nor to the person already given Task 2: ways.

3

The remaining 4 tasks go to the remaining 4 persons in ways. Total .

✓ Check

With Task 2 at person 3 or 4 there are assignments; in of them Task 1 is at person 1 or 2; .

⚠ Common trap

(C) 192 gives Task 1 four choices, forgetting that Task 2's person is already taken. The source key (B) 180 does not fit either count.

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Permutations & Combinations — Preparation

This question tests your understanding of Permutations & Combinations, a key topic in the Quantitative Aptitude section. The detailed solution above uses a step-by-step approach to show the reasoning, and where available, a shortcut that helps you solve similar questions in under 90 seconds during the actual exam.

Permutations count arrangements where order matters, while combinations count selections where order does not matter. This topic covers the fundamental principle of counting, factorials, nPr and nCr, arrangements of letters in a word (including repeated letters), circular arrangements, and selecting committees or teams with conditions. The hardest part is deciding whether a question needs a permutation or a combination. Ask yourself whether swapping two chosen items gives a new outcome. If it does, order matters. Conditions such as "two people must sit together" are handled by treating them as a single unit, and "at least one" questions are usually easiest to solve as total minus none. Practise the permutation and combination questions below, each with a step-by-step solution showing how to set up the count.