NIMCET 2011
A random variable has the following probability distribution: : , , , , , , , , : , , , , , , , , The value of is
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Answer: Option A —
Detailed Solution
Total probability is : .
The sum of the first odd numbers is , so and .
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.⚠ Common trap
Option (C) is , the probability of one value, not .Quick tip
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Probability Distributions — Preparation
This question tests your understanding of Probability Distributions, a key topic in the Quantitative Aptitude section. The detailed solution above uses a step-by-step approach to show the reasoning, and where available, a shortcut that helps you solve similar questions in under 90 seconds during the actual exam.
A random variable assigns a number to each outcome of a random experiment, and its probability distribution lists the probability of each value. This topic covers discrete random variables and their probability mass functions, continuous random variables and their probability density functions, and the cumulative distribution function. It also covers the expected value (mean) E(X) = sum of x p(x), the variance Var(X) = E(X^2) - [E(X)]^2, and the standard deviation. A common question type gives a probability distribution with an unknown constant k. Since all probabilities must add up to 1 (or the density must integrate to 1), you can find k first and then answer the rest of the question. Questions also ask you to build the distribution from a situation, such as the number of heads when three coins are tossed. Practise the probability distribution questions below, each with a step-by-step solution.