MAH MCA CET 2025
The number of parallelograms formed by a set of parallel lines intersecting another set of parallel lines is
Answer (Detailed Solution Below)View answer ▾Hide ▴
Answer: Option D — 18
Detailed Solution
Apply the core formula / reasoning rule:
Choose any lines from each set .
✓ Check
Direct evaluation yields 18, matching option (D).
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Ask a doubtMore Straight Line Questions
View all ›- Q1.Let be a point on the straight line which is equidistant from the coordinate axes. Then the point will lie only in:
- Q2.A line perpendicular to the line segment joining the points and divides it in the ratio . The equation of the line is
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- Q4.Let a, b, c, d be non-zero numbers. If the point of intersection of the lines and lies in the fourth quadrant and is equidistant from the two axes, then
- Q5.The range of values of in the interval such that the points and lie on the same side of the line is
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Straight Line — Preparation
This question tests your understanding of Straight Line, a key topic in the Quantitative Aptitude section. The detailed solution above uses a step-by-step approach to show the reasoning, and where available, a shortcut that helps you solve similar questions in under 90 seconds during the actual exam.
The straight line is the most fundamental topic in coordinate geometry. It covers the slope of a line, the angle between two lines, conditions for parallel and perpendicular lines, and the different forms of the equation of a line: slope-intercept, point-slope, two-point, intercept and normal forms. Exam questions also test the perpendicular distance of a point from a line, the distance between two parallel lines, the point of intersection of two lines, concurrency of three lines, and families of lines passing through an intersection point. Remember that two lines are perpendicular when the product of their slopes is -1 and parallel when their slopes are equal. Picking the right form of the equation for the information given is the main skill. Practise the straight line questions below, each with a step-by-step solution.