Permutations & Combinations Questions with Solutions
Permutations count arrangements where order matters, while combinations count selections where order does not matter. This topic covers the fundamental principle of counting, factorials, nPr and nCr, arrangements of letters in a word (including repeated letters), circular arrangements, and selecting committees or teams with conditions. The hardest part is deciding whether a question needs a permutation or a combination. Ask yourself whether swapping two chosen items gives a new outcome. If it does, order matters. Conditions such as "two people must sit together" are handled by treating them as a single unit, and "at least one" questions are usually easiest to solve as total minus none. Practise the permutation and combination questions below, each with a step-by-step solution showing how to set up the count.
- Q21.
There are 8 students appearing in an examination of which 3 have to appear in Mathematics paper and the remaining 5 in different subjects. Then, the number of ways they can be made to sit in a row, if the candidates in Mathematics cannot sit next to each other is
A. 2400B. 16200C. 4200D. 14400easyAsked in NIMCET 2014View solution āŗ - Q22.
If , then the value of is
A. 2B. 4C. 9D. 42easyAsked in NIMCET 2015View solution āŗ - Q23.
How many 3-digit numbers divisible by 5 can be formed using the digits 2, 3, 5, 6, 7 and 9, without repetition of digits?
A. 216B. 20C. 120D. 24easyAsked in NIMCET 2015View solution āŗ - Q24.
A student council has 10 members. From these, one President, one Vice-President, one Secretary, one Joint-Secretary and two Executive Committee members have to be elected. In how many ways can this be done?
A. 151200B. 75600C. 37800D. 18900easyAsked in NIMCET 2018View solution āŗ - Q25.
Ten points are marked on a straight line and eleven points are marked on another straight line. How many triangles can be constructed with vertices from among the above points?
A. 495B. 550C. 1045D. 2475easyAsked in NIMCET 2019View solution āŗ - Q26.
How many 4-digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9 which are divisible by 5, if none of the digits is repeated?
A. 216B. 60C. 24D. 25easyAsked in NIMCET 2019View solution āŗ - Q27.
The value of is
A. B. C. D.easyAsked in NIMCET 2024View solution āŗ - Q28.
Number of permutations of the letters of the word BANGLORE such that the string ANGLE appears together in all permutations, is
A. 120B. 24C. 720D. 1228easyAsked in NIMCET 2025View solution āŗ - Q29.
Number of three-digit numbers that can be formed using 0, 1, 2, 3 and 5, where these digits are allowed to repeat any number of times, is equal to
A. 115B. 100C. 125D. 140easyAsked in NIMCET 2025View solution āŗ