MAH LLB 3 Year CET 2 April Shift-2 2026
In which of the following expressions will the expression 'Q < S' be definitely true?
Answer (Detailed Solution Below)View answer ▾Hide ▴
Answer: Option C —
Detailed Solution
In (C), read from Q upwards: , and .
Chaining them gives , so is definitely true.
✓ Check
In (A) gives ; in (B) gives ; in (D) the signs and point opposite ways, so Q and S cannot be compared.⚠ Common trap
(D) tempts because appears in it, but the chain breaks at .Quick tip
Chain only signs that point the same way. In (C): , so .
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Inequalities (Reasoning) — Preparation
This question tests your understanding of Inequalities (Reasoning), a key topic in the Logical Reasoning section. The detailed solution above uses a step-by-step approach to show the reasoning, and where available, a shortcut that helps you solve similar questions in under 90 seconds during the actual exam.
Coded inequality questions give statements comparing several elements with symbols, such as P > Q >= R < S, and ask which conclusions definitely follow. In coded versions, the symbols are replaced by others (for example, @ means "greater than"), which must be decoded first. To combine statements, link the common elements into a single chain. A conclusion follows only if the chain connects the two elements with signs all pointing in the same direction. If the signs point in opposite directions, as in A > B < C, no definite relationship exists between A and C. When one sign in the chain is strict (> or <) and the other is not (>= or <=), the result is strict. Watch for "either-or" cases, where two conclusions about the same pair together cover every possibility, such as A >= B and A < B. Practise the inequality questions below. Each solution shows the combined chain.